Question: Katrina wants to estimate the proportion of adultAmericans who read
Katrina wants to estimate the proportion of adultAmericans who read at least 10 books last year. To do so, she obtains a simple random sample of 100 adult Americans and constructs a 95% conﬁdence interval. Matthew also wants to estimate the proportion of adult Americans who read atleast 10 books last year. He obtains a simple random sample of 400 adult Americans and constructs a 99% conﬁdence interval.Assuming both Katrina and Matthew obtained the same point estimate, whose estimate will have the smaller margin of error? Justify your answer.
Answer to relevant Questions(a) Find the t-value such that the area in the right tail is 0.10 with 25 degrees of freedom. (b) Find the t-value such that the area in the right tail is 0.05 with 30 degrees of freedom. (c) Find the t-value such that the ...Lower bound: 15, upper bound: 35 Determine the point estimate of the population mean and margin of error for each conﬁdence interval. Suppose for a random sample of 1001 Americans age 15 or older, the mean amount of time spent eating or drinking per day is 1.22 hours with a standard deviation of 0.65 hour. (a) A histogram of time spent eating and drinking ...The trade volume of a stock is the number of shares traded on a given day. The following data,in millions (so that 2.45 represents 2,450,000 shares traded), represent the volume of Harley-Davidson stock traded for a random ...A researcher wanted to determine the mean number of hours per week (Sunday through Saturday) the typical person watches television. Results from the Sullivan Statistics Survey indicate that s = 7.5 hours. (a) How many people ...
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