Let f be differentiable on (0, 1) and suppose that Show that [f(x) = exf(x)/ex.] linn(f(x) +f'(x))
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linn(f(x) +f'(x)) = L.
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Let hx e x fx Then hx e x fx fx so that by hypothesis Give 0 there e...View the full answer
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Related Book For
Introduction to Real Analysis
ISBN: 978-0471433316
4th edition
Authors: Robert G. Bartle, Donald R. Sherbert
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