Let F 1 and F 2 be d.f.s, and let G be their convolution, G = F

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Let F1and F2be d.f.s, and let G be their convolution, G = F1* F2. Then:

(i) If F1 is absolutely continuous with respect to Lebesgue measure with p.d.f. p1, it follows that G is absolutely continuous with respect to Lebesgue measure with p.d.f. p given by

P1(u – y)d F2(y). p(u) =

(ii) Furthermore, if F2 is also absolutely continuous with respect to Lebesgue measure with p.d.f. p2, then

Let F1 and F2 be d.f.s, and let G be

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