# Question

Let x02 be a particular value of x2. Find the value of x02 such that

a. P(x2 > x02) = .10 for n = 12

b. P(x2 > x02) = .05 for n = 9

c. P(x2 > x02) = .025 for n = 5

a. P(x2 > x02) = .10 for n = 12

b. P(x2 > x02) = .05 for n = 9

c. P(x2 > x02) = .025 for n = 5

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