Let x[n] = cos(2n/5) and v[n] be the sequence obtained by applying a 32-point rectangular window to
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Let x[n] = cos(2πn/5) and v[n] be the sequence obtained by applying a 32-point rectangular window to x[n] before computing V(ejω). Sketch |V(ejω) for –π ≤ ω ≤ π, labeling the frequencies of all peaks and the first nulls on either side of the peak. In addition, label the amplitudes of the peaks and the strongest side lobe of each peak.
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We have Therefore Ve j looks like un Ve The rectangular windows trans...View the full answer
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Related Book For
Discrete Time Signal Processing
ISBN: 978-0137549207
2nd Edition
Authors: Alan V. Oppenheim, Rolan W. Schafer
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