Lyme disease is the leading tick borne disease in the United States and Europe. Diagnosis of the
Question:
P(L) = 0.00207
P(LC) = 0.99793
P(1| L) = 0.937
P(2| L) = 0.063
P(1| LC) = 0.03
P(2| LC) = 0.97
a. For each of the given probabilities, write a sentence giving an interpretation of the probability in the context of this problem.
b. Use the given probabilities to construct a “hypothetical 1000” table with columns corresponding to whether or not a person has Lyme disease and rows corresponding to whether the blood test is positive or negative.
c. Notice the form of the known conditional probabilities; for example, P(1| L) is the probability of a positive test given that a person selected at random from the population actually has Lyme disease. Of more interest is the probability that a person has Lyme disease, given that the test result is positive. Use the table constructed in Part (b) to compute this probability.
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: