# Question

Minor league baseball is seen by many as one of the few remaining forms of affordable sports entertainment still available to families. (See “It’s a Homerun: Customer Service Greatness in the Minor Leagues,” D. Carter, D. Rovell.) If a random sample of 40 minor league ball-parks is surveyed to estimate the average cost of a hot dog at minor league parks throughout the country, and the average hot dog price for the sample was $1.38.

a. Build a 99% confidence interval estimate of the average cost of a hot dog for the population of minor league ballparks represented here. Assume the standard deviation of hot dog prices for the population of ballparks is known to be $.22.

b. Interpret the interval that you produced in part a.

a. Build a 99% confidence interval estimate of the average cost of a hot dog for the population of minor league ballparks represented here. Assume the standard deviation of hot dog prices for the population of ballparks is known to be $.22.

b. Interpret the interval that you produced in part a.

## Answer to relevant Questions

Each year, the American Federation of Teachers (AFT) reports the state-by-state average salary for teachers in public schools. In a recent study, the AFT reported an average salary of $60,583 for teachers in California, ...The average annual expense for groceries in a 2012 random sample of 600 US households is $8562. If the standard deviation of grocery expenses in the population of US households is $1230, compute the a. Standard error of the ...A simple random sample of size 3 has produced sample values 120, 130, and 140. Assume the population distribution of values is normal. a. Compute the sample average, x, and the sample standard deviation, s. b. Show the 95% ...CompuTrade, an online stock-trading service, has over 25,000 clients. To estimate the average number of trades made last month by CompuTrade’s clients, you take a simple random of 250 clients and find the average number of ...Suppose you were to draw all possible samples of size 81 from a large population with a mean (µ) of 54.0 and a standard deviation (σ) of 18.0. You then compute the mean (x) for each sample. From the long list of sample ...Post your question

0