Question: On any given day the probability that a randomly selected
On any given day, the probability that a randomly selected adult male in the United States drinks coffee is .51 ( 51%), and the probability that he drinks alcohol is .31 (31%). (http://www.ars.usda.gov/SP2UserFiles/Place/12355000/ars.usda.gov/SP2UserFiles/Place/12355000/pdf/DBrief/6_beverage_choices_adults_0708.DBrief/6_beverage_choices_adults_0708. pdf) What assumption would we have to make in order to use Rule 3 to conclude that the probability that a person drinks both is (.51) × (.31) = .158? Do you think that assumption holds in this case? Explain.
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