# Question

One of the emission spectral lines for Be3+ has a wave-length of 253.4 nm for an electronic transition that begins in the state with n = 5. What is the principal quantum number of the lower-energy state corresponding to this emission?

## Answer to relevant Questions

The Heisenberg uncertainty principle can be expressed in the form where E represents energy and t represents time. Show that the units for this form are the same as the units for the form used in this chapter: An electron in a one- dimensional box requires a wavelength of 8080 nm to excite an electron from the n = 2 to the n = 3 energy level. Calculate the length of this box. Carbon absorbs energy at a wavelength of 150 nm. The total amount of energy emitted by a carbon sample is 1.98 × 105 J. Calculate the number of carbon atoms present in the sample, assuming that each atom emits one photon. The wave function for the 2pz orbital in the hydrogen atom is Where a0 is the value for the radius of the first Bohr orbit in meters (5.29 × 10-11), σ is Zr/a0, r is the value for the distance from the nucleus in meters, ...Write the expected electron configurations for the following atoms: Sc, Fe, P, Cs, Eu, Pt, Xe, and Br.Post your question

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