A parallel-plate capacitor has a plate area A and a separation d. A metal slab of thickness
Question:
A parallel-plate capacitor has a plate area A and a separation d. A metal slab of thickness t and area A is inserted between the plates.
(a) Show that the capacitance is given by C = є0A/(d - t), regardless of where the metal slab is placed.
(b) Show that this arrangement can be considered to be a capacitor of separation a in series with one of separation b, where a + b + t = d.
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ISBN: 978-0195134889
1st Edition
Authors: Edmund G. Seebauer, Robert L. Barry
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