# Question: Prove directly that P E F P E FG P G F P E FGc P Gc F

Prove directly that

P(E|F) = P(E|FG)P(G|F) + P(E|FGc)P(Gc|F)

P(E|F) = P(E|FG)P(G|F) + P(E|FGc)P(Gc|F)

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