Prove statement 6 of theorem A. |f(x) g(x) - 1.M = |f(x) g(x) - Lg(x) + Lg(x)
Question:
|f(x) g(x) - 1.M = |f(x) g(x) - Lg(x) + Lg(x) - LM|
= |g(X) [f(x) - L] + L[g(x) - M]|
¤ |g(x) ||f(x) - L| + |L|| g(X) - M|
Now show that if
Then there is a number δ1 such that
0
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lim g(x)M
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Suppose And f xgx LM gx f x L L gx M as shown in the text Choose 1 1 Si...View the full answer
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