# Question: Prove Theorem 6 1 Theorem 6 1 The mean and the variance

Prove Theorem 6.1.

Theorem 6.1

The mean and the variance of the uniform distribution are given by

µ = α + β / 2 and σ2 = 1/12 (β – α)2

Theorem 6.1

The mean and the variance of the uniform distribution are given by

µ = α + β / 2 and σ2 = 1/12 (β – α)2

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