A radioactive 210Po nucleus emits an particle of charge +2e and energy 5.30 MeV. Assume that

A radioactive 210Po nucleus emits an α particle of charge +2e and energy 5.30 MeV. Assume that just after the α particle is formed and escapes from the nucleus, it is a distance R from the center of the daughter nucleus 206Pb, which has a charge +82e. Calculate R by setting the electrostatic potential energy of the two particles at this separation equal to 5.30 MeV. (Neglect the size of the α particle.)