# Question

Refer to Exercise 10.109.

a. Determine a 95% confidence interval for the difference between the mean heights of cross-fertilized and self-fertilized Zea mays.

b. Repeat part (a) for a 99% confidence level.

a. Determine a 95% confidence interval for the difference between the mean heights of cross-fertilized and self-fertilized Zea mays.

b. Repeat part (a) for a 99% confidence level.

## Answer to relevant Questions

Refer to Exercise 10.110. a. Determine a 90% confidence interval for the additional sleep that would be obtained, on average, by using laevohysocyamine hydrobromide. b. Repeat part (a) for a 98% confidence level. Refer to Exercise 10.114 and obtain a 98% confidence interval for the mean increase of the serum 25(OH)D concentration after 12 weeks of drinking fortified orange juice. Explain exactly how a paired t-test can be formulated as a one-mean t-test. A variable of two populations has a mean of 40 and a standard deviation of 12 for one of the populations and a mean of 40 and a standard deviation of 6 for the other population. Moreover, the variable is normally distributed ...x1 = 10, s1 = 4, n1 = 15, x2 = 12, s2 = 5, n2 = 15 a. Two-tailed test, α = 0.05 b. 95% confidence interval We have provided summary statistics for independent simple random samples from two populations. In each case, use ...Post your question

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