# Question

Refer to Exercise 10.43 and determine a 95% confidence interval for the difference between the mean number of native species in the two regions.

## Answer to relevant Questions

Why do you need to know the sampling distribution of the difference between two sample means in order to perform a hypothesis test to compare two population means? In this section, we introduced the pooled t-test, which provides a method for comparing two population means. In deriving the pooled t-test, we stated that the variable cannot be used as a basis for the required test ...Suppose that you want to perform a hypothesis test to compare the means of two populations, using independent simple random samples. Assume that the two distributions (one for each population) of the variable under ...x1 = 20, s1 = 6, n1 = 20, . x2 = 24, s2 = 2, n2 = 15 a. Left-tailed test, α = 0.05 b. 90% confidence interval We have provided summary statistics for independent simple random samples from two populations. In each case, ...Refer to Exercise 10.72 and determine a 98% confidence interval for the difference, μ1 − μ2, between the mean sediment ammonium concentrations in CCB and LLM.Post your question

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