Question: Refer to Exercise 10 43 and determine a 95 confidence interval
Refer to Exercise 10.43 and determine a 95% confidence interval for the difference between the mean number of native species in the two regions.
Answer to relevant QuestionsWhy do you need to know the sampling distribution of the difference between two sample means in order to perform a hypothesis test to compare two population means? In this section, we introduced the pooled t-test, which provides a method for comparing two population means. In deriving the pooled t-test, we stated that the variable cannot be used as a basis for the required test ...Suppose that you want to perform a hypothesis test to compare the means of two populations, using independent simple random samples. Assume that the two distributions (one for each population) of the variable under ...x1 = 20, s1 = 6, n1 = 20, . x2 = 24, s2 = 2, n2 = 15 a. Left-tailed test, α = 0.05 b. 90% confidence interval We have provided summary statistics for independent simple random samples from two populations. In each case, ...Refer to Exercise 10.72 and determine a 98% confidence interval for the difference, μ1 − μ2, between the mean sediment ammonium concentrations in CCB and LLM.
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