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Refer to Exercise 6 17 Calculate the following probabilities a P A1 B2

Refer to Exercise 6.17. Calculate the following probabilities.

a. P(A1∣B2)

b. P(B2∣A1)

c. Did you expect the answers to parts (a) and (b) to be reciprocals? In other words, did you expect that P(A1∣B2) = 1/P(B2∣A1)? Why is this impossible (unless both probabilities are 1)?

a. P(A1∣B2)

b. P(B2∣A1)

c. Did you expect the answers to parts (a) and (b) to be reciprocals? In other words, did you expect that P(A1∣B2) = 1/P(B2∣A1)? Why is this impossible (unless both probabilities are 1)?

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