# Question: Refer to Exercise 6 46 Answer the following questions using the

Refer to Exercise 6.46. Answer the following questions using the combined data for both depths.

a. Use the Wilcoxon rank sum test to assess whether there is a difference in population abundances between the sites within and outside the oil trajectory. Use α = .05.

b. What are the required conditions for the techniques used in part (a)?

c. Are the required conditions satisfied?

d. Discuss any differences in the conclusions obtained using the t procedures and the Wilcoxon rank sum test.

a. Use the Wilcoxon rank sum test to assess whether there is a difference in population abundances between the sites within and outside the oil trajectory. Use α = .05.

b. What are the required conditions for the techniques used in part (a)?

c. Are the required conditions satisfied?

d. Discuss any differences in the conclusions obtained using the t procedures and the Wilcoxon rank sum test.

## Answer to relevant Questions

Refer to Exercise 6.46. The researchers also examined the effect of depth on population abundance. In exercise a. Plot the four data sets using side-by-side boxplots to demonstrate the effect of depth on population ...Refer to Exercise 6.50. a. Compare the mean drops in blood pressure for the low-dose group and the high-dose group. Use α = .05 and report the level of significance. b. Estimate the size of the difference in the mean ...Company officials are concerned about the length of time a particular drug retains its potency. A random sample (sample 1) of 10 bottles of the product is drawn from current production and analyzed for potency. A second ...Defining the Problem (1). Lead is an environmental pollutant especially worthy of attention because of its damaging effects on the neurological and intellectual development of children. Morton et al. (1982) collected data on ...Find the value that locates an area α in the upper tail of the F distribution; that is, find Fa for the following values of α and degrees of freedom. a. α = .05, df1 = 6, df2 = 45 b. α = .025, df1 = 8, df2 = 55 c. α ...Post your question