# Question: Refer to the previous exercise a Predict the math SAT score

Refer to the previous exercise.

a. Predict the math SAT score for a student who has a verbal SAT = 800.

b. The correlation is 0.5. Interpret the prediction in part a in terms of regression toward the mean.

Previous exercise

All students who attend Lake Wobegon College must take the math and verbal SAT exams. Both exams have a mean of 500 and a standard deviation of 100. The regression equation relating y = math SAT score and x = verbal SAT score is = 250 + 0.5x.

a. Predict the math SAT score for a student who has a verbal SAT = 800.

b. The correlation is 0.5. Interpret the prediction in part a in terms of regression toward the mean.

Previous exercise

All students who attend Lake Wobegon College must take the math and verbal SAT exams. Both exams have a mean of 500 and a standard deviation of 100. The regression equation relating y = math SAT score and x = verbal SAT score is = 250 + 0.5x.

**View Solution:**## Answer to relevant Questions

Refer to the previous exercise. a. Find the predicted mileage for the Toyota Corolla, which weighs 2590 pounds. b. Find the residual for the Toyota Corolla, which has observed mileage of 38. c. Sketch a graphical ...For a class of 100 students, the teacher takes the 10 students who performed poorest on the midterm exam and enrolls them in a special tutoring program. Both the midterm and final have a class mean of 70 with standard ...A regression analysis is conducted with 25 observations. a. What is the df value for inference about the slope β? b. Which two t test statistic values would give a P-value of 0.05 for testing H0: β = 0 against Ha: β ≠ ...Suppose the regression line μy = -10,000 + 1000x models the relationship for the population of working adults in Canada between x = age and the mean of y = annual income (in Canadian dollars). The conditional distribution ...Using the context of the previous exercise, explain the difference between the purpose of a 95% prediction interval (PI) for an observation and a 95% confidence interval (CI) for the mean of y at a given value of x. Why ...Post your question