Refer to the previous exercise. The output shows the result of comparing the mean responses on parties and sports.
Paired T for parties - sports

Difference 10 12.8000 22.5477 7.1302
95% CI for mean difference: (-3.3297, 28.9297)
T-Test of mean difference = 0 (vs not = 0):
T-Value = 1.80 P-Value = 0.106
a. Explain how to interpret the reported 95% confidence interval.
b. State the hypotheses to which the P-value refers, and interpret its value.
c. Explain the connection between the results of the test and the confidence interval.
d. What assumptions are necessary for these inferences to be appropriate?

Transcribed Image Text:

StDev SE Mean 10 21.8000 18.5760 5.8742 10 9.0000 8.3799 2.6499 Difference 10 12.8000 22.5477 7.1302 Me ann parties sports