# Question: Show that the estimator of Exercise 10 5 is a sufficient

Show that the estimator of Exercise 10.5 is a sufficient estimator of the variance of a normal population with the known mean µ.

Exercise 10.5

Show that is a minimum variance unbiased estimator of the mean µ of a normal population.

Exercise 10.5

Show that is a minimum variance unbiased estimator of the mean µ of a normal population.

**View Solution:**## Answer to relevant Questions

Given a random sample of size n from a population that has the known mean µ and the finite variance σ2, show that Use the method of maximum likelihood to rework Exercise 10.53. In exercise Given a random sample of size n from a Poisson population, use the method of moments to obtain an estimator for the parameter λ. Given a random sample of size n from a Pareto population (see Exercise 6.21 on page 184), use the method of maximum likelihood to find a formula for estimating its parameter α. Let X1, X2, . . . , Xn be a random sample of size n from the uniform population given by Show that if Y1 and Yn are the first and nth order statistic, any estimator Θ such that Can serve as a maximum likelihood estimator of ...The size of an animal population is sometimes estimated by the capture-recapture method. In this method, n1 of the animals are captured in the area under consideration, tagged, and released. Later, n2 of the animals are ...Post your question