Starting with an initial speed of 5.00 m/s at a height of 0.300 m, a 1.50-kg ball
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Starting with an initial speed of 5.00 m/s at a height of 0.300 m, a 1.50-kg ball swings downward and strikes a 4.60-kg ball that is at rest, as the drawing shows.
(a) Using the principle of conservation of mechanical energy, find the speed of the 1.50 kg ball just before impact.
(b) Assuming that the collision is elastic, find the velocities (magnitude and direction) of both balls just after the collision.
(c) How high does each ball swing after the collision, ignoring air resistance?
Transcribed Image Text:
1.50 kg 0.300 m 5.00 m/s 4.60 kg
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a Applying the principle of energy conservation to the 150kg ball we have mv 2 f mgh f mv 0 2 mgh 0 ...View the full answer
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