Evaluate C F r' ds, F = (x 2 + y 2 ) -1 [-y,
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Evaluate ∫C F • r' ds, F = (x2 + y2)-1[-y, x], C: x2 + y2 = 1, z = 0, oriented clockwise. Why can Stokes’s theorem not be applied? What (false) result would it give?
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Stokes Theorem cannot be applied because the vector field F is not conservativ...View the full answer
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