Find e -0.25 and e -0.75 by linear interpolation of e -x with x 0 = 0,

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Find e-0.25 and e-0.75 by linear interpolation of e-x with x0 = 0, x1 = 0.5 and x0 = 0.5, x1 = 1, respectively. Then find p2(x) by quadratic interpolation of e-x with x0 = 0, x1 = 0.5, x2 = 1 and from it e-0.25 and e-0.75. Compare the errors. Use 4S-values of e-x.

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