Same task as in Prob. 23, for f(x) = |x| / (- < x ). Why is
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Same task as in Prob. 23, for f(x) = |x| /π (-π < x π). Why is E* now much smaller (by a factor 100, approximately!)?
Data from Prob. 23
Compute the minimum square error for f(x) = x/π (-π < x < π) and trigonometric polynomials of degree N = 1, · · ·, 5.
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First calculate the minimum square error The same technique as in Prob 23 will be used to find t...View the full answer
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