Show that Q() must be periodic with period 2 and, therefore, n = 0, 1, 2,
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Show that Q(θ) must be periodic with period 2π and, therefore, n = 0, 1, 2, · · · in (25) and (26). Show that this yields the solutions Qn = cos nθ, Q*n = sin nθ, Wn = Jn(kr), n = 0, 1, · · ·.
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First we verify that Q 0 Q 1 Q 2 Q n 1 Q 0 W 0 2 0 where in the last ...View the full answer
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