Show that y = uv with v(x) = exp (-1/2 p(x) dx) gives from the ODE
Question:
Show that y = uv with v(x) = exp (-1/2 ∫ p(x) dx) gives from the ODE y" + p(x)y' + q(x)y = 0 the ODE
u" + [q(x) - 1/4p(x)2 - 1/2p' (x)] u = 0,
not containing the first derivative of u.
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an explicit solution is y pxy qxy 0 where y0 y...View the full answer
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