Solve, showing details: y' 1 = y 2 - 5 sin t y' 2 = -4y 1
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Solve, showing details:
y'1 = y2 - 5 sin t
y'2 = -4y1 + 17 cos t
y1(0) = 5, y2(0) = 2
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y1 2 y2 5 The slope at x0 is y2 5 sin t an...View the full answer
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