Use p 2 (x) in (18) and the values of erf x, x = 0.2, 0.4, 0.6
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Use p2(x) in (18) and the values of erf x, x = 0.2, 0.4, 0.6 in Table A4 of App. 5, compute erf 0.3 and the error. (4S-exact erf 0.3 = 0.3286).
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