An incompressible liquid of specific volume (v_{l}), is in equilibrium with its own vapour and an inert

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An incompressible liquid of specific volume \(v_{l}\), is in equilibrium with its own vapour and an inert gas in a closed vessel. The vapour obeys the law

\[p(v-b)=\Re T\]

Show that

\[\ln \left(\frac{p_{v}}{p_{0}}\right)=\frac{1}{\Re T}\left\{\left(p-p_{0}\right) v_{\ell}-\left(p_{v}-p_{0}\right) b\right\}\]

where \(p_{0}\) is the vapour pressure when no inert gas is present, and \(p\) is the total pressure.

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Related Book For  answer-question

Advanced Thermodynamics For Engineers

ISBN: 9780080999838

2nd Edition

Authors: D. E. Winterbone, Ali Turan

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