Prove directly from the definition of (M(Lambda)) and (bar{M}(Lambda)) in Eq. (4.6.14) that (i sigma^{2} bar{chi}^{*}) transforms

Question:

Prove directly from the definition of $M(\Lambda)$ and $\bar{M}(\Lambda)$ in Eq. (4.6.14) that $i \sigma^{2} \bar{\chi}^{*}$ transforms with $M(\Lambda)$ and $-i \sigma^{2} \psi^{*}$ transforms with $\bar{M}(\Lambda)$ and hence verify that the charge conjugate of the Dirac spinor in the chiral representation in Eq. (4.6.44) transforms as a Dirac spinor.

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