In Exercises show that the function represented by the power series is a solution of the differential
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In Exercises show that the function represented by the power series is a solution of the differential equation.
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y = n=0 (-1)¹ x2n (2n)! y" + y = 0
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2n 1 x v 2 n0 n1 1 2nxn1 ...View the full answer
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