In Exercises use substitution and partial fractions to find the indefinite integral. I ex (ex + 1)(ex
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In Exercises use substitution and partial fractions to find the indefinite integral.
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I ex (e²x + 1)(ex - 1) dx
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Let u e du ex dx 1 A x 1Xu 1 1u 1 ezx 1 Au 1 Bu Cu 1 When u 1 ...View the full answer
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