Show that the surface area of the cone z = kx + y, k > 0, over
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Show that the surface area of the cone z = k√x² + y², k > 0, over the circular region x² + y² ≤ r² in the xy-plane is πr²√k² + 1 (see figure).
Transcribed Image Text:
N z=k√√x² + y² R: x² + y² ≤r² y
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