Assume that the outside temperature varies as T(t) = 15 + 5 sin(t/12) where t = 0

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Assume that the outside temperature varies as T(t) = 15 + 5 sin(πt/12) where t = 0 is 12 noon. A house is heated to 25°C at t = 0 and after that, its temperature y(t) varies according to Newton’s Law of Cooling (Figure 6):

dy = dt = -0.1(y(t) - T(t))

Use Exercise 45 to solve for y(t). 25 20 15 10 5 y (C) y(t) T(t) 12 24 36 48 60 72 84 -t (hours)


Data From Exercise 45

Let a, b, r be constants. Show that

is a general solution of y = cekt + a + bk dy dt = k sin rt-r cos rt k + r -k(y - a -b sinrt)

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Calculus

ISBN: 9781319055844

4th Edition

Authors: Jon Rogawski, Colin Adams, Robert Franzosa

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