Explain why the Error Bound for S N decreases by 1/16 if N is increased to 2N.
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Explain why the Error Bound for SN decreases by 1/16 if N is increased to 2N. Compute the actual error in SN for ∫π0 sin x dx for N = 4, 8, 16, 32, and 64. Does the actual error seem to decrease by 1/16 as N is doubled?
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Thus we see that since N is raised to the fourth power in the denominator the Error Bound for Sy dec...View the full answer
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