Let (u) = u q and g(x) = x p/q . Assume that g is differentiable. (a)
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Let ƒ(u) = uq and g(x) = xp/q. Assume that g is differentiable.
(a) Show that ƒ(g(x)) = xp (recall the Laws of Exponents).
(b) Apply the Chain Rule and the Power Rule for whole-number exponents to show that ƒ'(g(x)) g'(x) = pxp−1.
(c) Then derive the Power Rule for xp/q.
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