Show that (x) 2x 3 2x sin x 1 has precisely one real root ...

We have f0 1 and f1 3 sin1 384 0 Therefore f has a root in the interval 10 Now s ...

Show that (x) = 2x 3 + 2x + sin x + 1 has precisely one real

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Show that ƒ(x) = 2x³ + 2x + sin x + 1 has precisely one real root.

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Calculus

ISBN: 9781319055844

4th Edition

Authors: Jon Rogawski, Colin Adams, Robert Franzosa

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Question Posted: Nov 23, 2023 08:16 AM

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Show that (x) = 2x 3 + 2x + sin x + 1 has precisely one real

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We have f0 1 and f1 3 sin1 384 0 Therefore f has a root in the interval 10 Now s...View the full answer

Calculus

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