Verify that function F(x) x tan 1 x 1 2 ln(x 2 1) is an antiderivative of (x) tan 1 x satisfying F(0) 0 Then use the result of Exercise 53 with x 1 3 to show that Use a calculator to compare the value of the left hand side with the partial sum S 4 of the series on the right 1 4 In 63 2 3 1 1 2(3) 1...

We have Fx tan x so that Fx is an antiderivative of tan setting x gives 1 3 Now ...

Verify that function F(x) = x tan 1 x 1/2 ln(x 2 + 1) is an

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Verify that function F(x) = x tan⁻¹ x − 1/2 ln(x² + 1) is an antiderivative of ƒ(x) = tan⁻¹ x satisfying F(0) = 0. Then use the result of Exercise 53 with x = √1/3 to show that

1 4 In 63 2 3 - - = 1 1.2(3) 1 3.4(32) + 1 5.6(3) 1 7.8(34) +.

Use a calculator to compare the value of the left-hand side with the partial sum S₄of the series on the right.

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Authors: Jon Rogawski, Colin Adams, Robert Franzosa

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Verify that function F(x) = x tan 1 x 1/2 ln(x 2 + 1) is an

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ग 1 4 In 6√3 2 3 - - = 1 1.2(3) 1 3.4(32) + 1 5.6(3³) 1 7.8(34) +.

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We have Fx tan x so that Fx is an antiderivative of tan setting x gives 1 3 Now ...View the full answer

Calculus

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