When a capacitor of capacitance C is charged by a source of voltage V, the power expended

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When a capacitor of capacitance C is charged by a source of voltage V, the power expended at time t is

P(t) = 12 R 5(e-1/RC-e-21/RC)

where R is the resistance in the circuit. The total energy stored in the capacitor is

= 5 W = P(t) dt

Show that W = 1/2 CV2.

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Related Book For  answer-question

Calculus

ISBN: 9781319055844

4th Edition

Authors: Jon Rogawski, Colin Adams, Robert Franzosa

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