We learn in trigonometry that sin x sin( x). Hence f(sin x) = f(sin[
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We learn in trigonometry that sin x ≡ sin(π − x). Hence f(sin x) = f(sin[π − x]). Now let f(x) = x sin x. Then x sin x = (π − x) sin(π − x) or x = π − x. Hence π = 2x and since x is any value we choose, so is π. What is wrong?
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