Suppose you evaluate dx/x using integration by parts. With u = 1/x and dv = dx,
Question:
Suppose you evaluate ∫ dx/x using integration by parts. With u = 1/x and dv = dx, you find that du = -1/x2 dx, v = x, and
You conclude that 0 = 1. Explain the problem with the calculation.
Transcribed Image Text:
/4-()- - /()«-- dx dx. dx = 1 + .2
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Related Book For
Calculus Early Transcendentals
ISBN: 978-0321947345
2nd edition
Authors: William L. Briggs, Lyle Cochran, Bernard Gillett
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