Therefore, f(-2) < 0 < f(2), but there is no value of c between -2 and 2
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Therefore, f(-2) < 0 < f(2), but there is no value of c between -2 and 2 for which f(c) = 0. Does this fact violate the Intermediate Value Theorem? Explain.
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Then f(-2) = -1 and f(2) = 1. f(x)
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Related Book For
Calculus Early Transcendentals
ISBN: 978-0321947345
2nd edition
Authors: William L. Briggs, Lyle Cochran, Bernard Gillett
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