If an object is dropped or thrown vertically, its height (in feet) after t seconds is H(t)

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If an object is dropped or thrown vertically, its height (in feet) after t seconds is H(t) = −16t2 + V0t + H0, where V0 is the initial speed of the object and H0 is its initial height.

a. Derive an expression for the acceleration of the object.

b. How does the acceleration vary with time?

c. What is the significance of the fact that the answer to part (a) is negative?

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Related Book For  answer-question

Calculus For Business, Economics And The Social And Life Sciences

ISBN: 9780073532387

11th Brief Edition

Authors: Laurence Hoffmann, Gerald Bradley, David Sobecki, Michael Price

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