Let f (x, y) = x 2 + y 2 4xy. Show that f does not
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Let f (x, y) = x2 + y2 − 4xy. Show that f does not have a relative minimum at its critical point (0, 0), even though it does have a relative minimum at (0, 0) in both the x and y directions.
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So 0 0 is a critical point and 0 0 is a saddle point The above is true but not asked for I...View the full answer
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Related Book For
Calculus For Business, Economics And The Social And Life Sciences
ISBN: 9780073532387
11th Brief Edition
Authors: Laurence Hoffmann, Gerald Bradley, David Sobecki, Michael Price
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