a. Show that the equation 3sin 2 + 5sincos = 2 cos 2 can be

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a. Show that the equation 3sin2θ + 5sinθcosθ = 2 cos2θ can be written in the form 3tan2θ + 5tanθ − 2 = 0.
b. Hence, solve the equation 3sin2θ+ 5sinθcosθ = 2 cos2θ for 0° ≤ θ ≤ 180°.

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