This code shows how CHEBFUN can be used with MATLAB ODE45 to give a "symbolic" look to your answer. The presence of the calling argument domain in the calling statement creates a Chebyshev polynomial for the results.

Note that additional operations on the results such as finding the maximum values etc. have become rather easier with this approach.
The maximum value of \(B\) is 0.25 and occurs at time 0.6931 for the parameters used in the example. These match the exact values from the analytical model.

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% consecutive reaction using ODE45 and CHEBFUN % A > B > C fun = k1 1.0; k2 = 2.0; = @(t,v) [-k1*v (1); k1*v (1) -k2*v (2)]; v = ode45 (fun, domain (0,3), [1 0]); % solves plot (v) % generates the plot c_max = max (v(:,2)) % finds what the maximum value is. diff( v(:,2)) % takes the derivative F = roots (F) % finds where the maximum occurs