A 50.00-mL solution of a weak acid HA (Ka = 5.00 10210) in water has a
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A 50.00-mL solution of a weak acid HA (Ka = 5.00 × 10210) in water has a pH = 5.650. Calculate the amount of water that must be added to reach a pH value of 6.650.
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Solution The pH of this solution can be calculated using the following equation pH log CHA x 1000 ...View the full answer
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