Given the following data: P4(s) + 6Cl(g) 4PCl3(g) P4(s) + 50(g) P4O10(S) PC13(g) + Cl(g) PCls
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Given the following data:
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P4(s) + 6Cl₂(g) →→→ 4PCl3(g) P4(s) + 50₂(g) P4O10(S) PC13(g) + Cl₂(g) PCls (g) PC13(g) + O₂(g) Cl₂PO(g) calculate AH for the reaction P4010(s) + 6PC15(g) AH = -1225.6 kJ AH = -2967.3 kJ AH = -84.2 kJ AH = -285.7 kJ 10Cl₂PO(g)
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Given data Eq1 P4s 6Cl2g 4PCl3 H12256 KJ Eq2 P4s 5O2g P4O10s H29673 KJ ...View the full answer
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Godswill Okorie
M.Sc chemistry specialization in organic chemistry, B.ed .I am having industry experience of seven years working with Ranbaxy nd Shimadzu analytical India by working as an application chemistry.I am having good practical experience on chromatography techniques,which later helped me in my teaching.I worked as PGT chemistry teacher with KV and APS.
As a teacher I was able to achieve good results with my students.I used to take 11th and 12th chemistry and science to classes 7th ,8th and ninth. While teaching I used to guide students for various carrier opportunities.
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