Derive Equation. d 2 yd 2 n 2 yn=0 by 2dy/d, rearrange to get dd(dyd) 2 =n
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Derive Equation. d2ydλ2−ϕn2yn=0 by 2dy/dλ, rearrange to get ddλ(dydλ)2=ϕn2yn2dydλ and solve using the boundary conditions dy/dλ = 0 at λ = 0.
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dy ny 0 d22 Multiply by 2 y 20 dy d dy d d d YPYP Manipulating the LHS d dy dy dy YP YP dy d dy d ...View the full answer
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